2t^2-t=2-1/t

Solution for 2t^2-t=2-1/t equation:

D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

2*t^2-t = 2-(1/t) // - 2-(1/t)

2*t^2-t+1/t-2 = 0

2*t^2-1*t^1+1*t^-1-2*t^0 = 0

(2*t^3-1*t^2-2*t^1+1*t^0)/(t^1) = 0 // * t^2

t^1*(2*t^3-1*t^2-2*t^1+1*t^0) = 0

t^1

2*t^3-t^2-2*t+1 = 0

{ 1, -1 }

1

t = 1

2*t^3-t^2-2*t+1 = 0

1

t-1

2*t^2+t-1

2*t^3-t^2-2*t+1

t-1

2*t^2-2*t^3

t^2-2*t+1

t-t^2

1-t

t-1

0

2*t^2+t-1 = 0

DELTA = 1^2-(-1*2*4)

DELTA = 9

DELTA > 0

t = (9^(1/2)-1)/(2*2) or t = (-9^(1/2)-1)/(2*2)

t = 1/2 or t = -1

t in { -1, 1/2, 1} 

t in { -1, 1/2, 1 }